Pow(x, n)
Implement pow(x, n), which calculates x raised to the power n (i.e. xn).
Example 1:
Input: x = 2.00000, n = 10 Output: 1024.00000
Example 2:
Input: x = 2.10000, n = 3 Output: 9.26100
Example 3:
Input: x = 2.00000, n = -2 Output: 0.25000 Explanation: 2-2 = 1/22 = 1/4 = 0.25
Constraints:
-100.0 < x < 100.0
-231 <= n <= 231-1
-104 <= xn <= 104
class Solution {
public:
// double myPow(double x, int n) {
// double ans=pow(x,n);
// return ans;
// }
double myPow(double x, int n) {
double ans=1,a=1;
if(n<0)
a=-1;
n=abs(n);
while(n>0)
{
if(n%2==1)
ans=ans*x;
x=x*x;
n/=2;
}
if(a==-1)
ans=1.0/ans;
return ans;
}
};