First Unique Character in a String
Given a string, find the first non-repeating character in it and return its index. If it doesn't exist, return -1.
Examples:
s = "leetcode" return 0. s = "loveleetcode" return 2.
Note: You may assume the string contains only lowercase English letters.
class Solution {
public:
int firstUniqChar(string s) {
int dp[26]={0};
for(auto ch: s)
{
dp[ch-'a']++;
}
for(int i=0;i<s.size();++i)
if(dp[s[i]-'a']==1)
return i;
return -1;
}
};