Find the Town Judge
In a town, there are N
people labelled from 1
to N
. There is a rumor that one of these people is secretly the town judge.
If the town judge exists, then:
- The town judge trusts nobody.
- Everybody (except for the town judge) trusts the town judge.
- There is exactly one person that satisfies properties 1 and 2.
You are given trust
, an array of pairs trust[i] = [a, b]
representing that the person labelled a
trusts the person labelled b
.
If the town judge exists and can be identified, return the label of the town judge. Otherwise, return -1
.
Example 1:
Input: N = 2, trust = [[1,2]] Output: 2
Example 2:
Input: N = 3, trust = [[1,3],[2,3]] Output: 3
Example 3:
Input: N = 3, trust = [[1,3],[2,3],[3,1]] Output: -1
Example 4:
Input: N = 3, trust = [[1,2],[2,3]] Output: -1
Example 5:
Input: N = 4, trust = [[1,3],[1,4],[2,3],[2,4],[4,3]] Output: 3
class Solution {
public:
int findJudge(int N, vector<vector<int>>& trust) {
if(N==1)return 1;
int indgree[N+1];
memset(indgree,0,sizeof(indgree));
int cnt=0,i;
for(auto v : trust )
{
indgree[v[0]]++;
}
for(int j=1;j<=N;++j)
if(indgree[j]==0)
{
++cnt;
i=j;
}
if(cnt!=1)
return -1;
else
{
cnt=0;
for(auto v : trust )
{
if(i==v[1])
++cnt;
}
}
if(cnt==N-1)
return i;
else
return -1;
}
};