Count Square Submatrices with All Ones
Given a m * n
matrix of ones and zeros, return how many square submatrices have all ones.
Example 1:
Input: matrix = [ [0,1,1,1], [1,1,1,1], [0,1,1,1] ] Output: 15 Explanation: There are 10 squares of side 1. There are 4 squares of side 2. There is 1 square of side 3. Total number of squares = 10 + 4 + 1 = 15.
Example 2:
Input: matrix = [ [1,0,1], [1,1,0], [1,1,0] ] Output: 7 Explanation: There are 6 squares of side 1. There is 1 square of side 2. Total number of squares = 6 + 1 = 7.
Constraints:
1 <= arr.length <= 300
1 <= arr[0].length <= 300
0 <= arr[i][j] <= 1
class Solution {
public:
int countSquares(vector<vector<int>>& matrix) {
int n=matrix.size(),m=matrix[0].size();
vector<vector<int> > mat(matrix.size(),vector<int>(matrix[0].size(),0));
int ans=0;
for(int i=0;i<n;++i)
{
for(int j=0;j<m;++j)
{
if(i==0||j==0)
{
mat[i][j]=matrix[i][j];
}else if(matrix[i][j]==1)
{
mat[i][j]=min(mat[i-1][j-1],min(mat[i-1][j],mat[i][j-1]))+matrix[i][j];
}else{
mat[i][j]=matrix[i][j];
}
ans=ans+mat[i][j];
}
}
return ans;
}
};