Corresponding to each test case, print the kth smallest element in a new line.
Expected Time Complexity: O(N).
Expected Auxiliary Space: O(1).
Example:
Input:
2
6
7 10 4 3 20 15
3
5
7 10 4 20 15
4
Output:
7
15
Explanation:
Testcase 1: 3rd smallest element in the given array is 7.
Testcase 2: 4th smallest elemets in the given array is 15.
#include <bits/stdc++.h>
using namespace std;
int main() {
//code
int t;
cin>>t;
while(t--)
{
int n,m,x,l=0;
cin>>n;
int a[100000];
memset(a,0,sizeof(a));
for(int i=0;i<n;++i){
cin>>x;
a[x]++;
}
cin>>m;
for(int i=0;i<100000;++i)
{
if(a[i]>0)
{
l+=a[i];
}
if(l>=m)
{
cout<<i<<endl;
break;
}
}
}
return 0;
}